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Carnot Cycle

The Carnot cycle is an idealized four-step reversible thermodynamic cycle consisting of two isothermal and two adiabatic processes that establishes the universal upper bound on heat engine efficiency between two thermal reservoirs: ηmax = 1 − TC / T_H.

The Carnot cycle is an idealized, quasi-static reversible thermodynamic cycle proposed by French military engineer and physicist Nicolas Léonard Sadi Carnot in his landmark 1824 monograph Réflexions sur la puissance motrice du feu (Reflections on the Motive Power of Fire). Operating a working substance between a high-temperature thermal reservoir at absolute temperature TH and a low-temperature thermal sink at absolute temperature TC, the cycle executes four successive reversible steps: (1) isothermal expansion at TH while absorbing heat QH, (2) adiabatic (isentropic) expansion that cools the working fluid from TH to TC, (3) isothermal compression at TC while rejecting waste heat |*Q*C|, and (4) adiabatic (isentropic) compression that warms the working fluid from TC back to TH.

Because every stage of the Carnot cycle is executed reversibly without friction, turbulence, or finite-temperature conductive heat transfer gradients, Carnot's theorem proves that no heat engine operating between two given thermal reservoirs at TH and TC can achieve a higher thermal efficiency η than a Carnot engine operating between those same reservoirs, regardless of the chemical or physical nature of the working fluid. Expressed in terms of absolute kelvin temperatures, the maximum thermodynamic efficiency is:

ηCarnot = Wnet / QH = (QH − |*Q*C|) / QH = 1 − |*Q*C| / QH = 1 − TC / TH

Historically, Carnot's analysis laid the conceptual foundation for Rudolf Clausius and William Thomson (Lord Kelvin) to formulate the second law of thermodynamics, define the absolute thermodynamic temperature scale, and establish entropy (S) as a path-independent state function via the Clausius equality ∮ δ*Q*rev / T = 0. Beyond mechanical steam and gas turbines, Carnot cycle thermodynamics governs cryogenic refrigeration, industrial heat pumps, solar thermochemical conversion, and geophysical fluid heat engines such as tropical cyclones.

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The Four Reversible Stages of the Carnot Heat Engine

Analytical Derivation for an Ideal Gas Working Fluid

Although Carnot's efficiency theorem is independent of the working substance, Emile Clapeyron (1834) and Rudolf Clausius (1850) illustrated the cycle quantitatively using n moles of a substance obeying the ideal gas law (PV = nRT) with constant heat capacity ratio γ = CP / CV. For an ideal gas, internal energy U(T) depends only on temperature (d*U* = nCV,m d*T*), and reversible adiabatic processes follow Poisson's law TVγ−1 = constant (or PVγ = constant). Across one complete clockwise loop on a pressure–volume (P–V) indicator diagram through states A → B → C → D → A:

  1. Stage 1 → 2 (A → B): Reversible Isothermal Expansion at TH. The gas starts at high pressure and small volume (PA, VA, TH) in thermal contact with the hot reservoir at TH. As the piston expands quasi-statically to volume VB, the gas temperature remains constant at TH, so Δ*U*AB = 0. By the first law of thermodynamics (Δ*U* = Q − W), the heat QH absorbed from the hot reservoir equals the expansion work performed by the gas:

QH = WAB = ∫VAVB P d*V* = ∫VAVB (nRTH / V) d*V* = nRTH ln(VB / VA) > 0 During this step, the entropy of the working gas increases by Δ*S*AB = QH / TH = nR ln(VB / VA).

  1. Stage 2 → 3 (B → C): Reversible Adiabatic (Isentropic) Expansion (TH → TC). The cylinder is thermally insulated from the reservoir (QBC = 0, Δ*S*BC = 0) and allowed to expand further from VB to VC. Because the gas performs positive expansion work at the expense of its own internal thermal kinetic energy, its temperature drops from TH to TC. The work done is WBC = −Δ*U*BC = nCV,m(TH − TC), and the adiabatic volume relation requires THVBγ−1 = TCVCγ−1.
  1. Stage 3 → 4 (C → D): Reversible Isothermal Compression at TC. The cylinder is placed in thermal contact with the cold sink at TC and compressed quasi-statically from VC to VD. Because T = TC is constant, Δ*U*CD = 0, and the work done on the gas is rejected as waste heat |*Q*C| into the cold reservoir:

|*Q*C| = −*Q*CD = −*W*CD = nRTC ln(VC / VD) > 0 The entropy of the working gas decreases by Δ*S*CD = −|*Q*C| / TC = −*nR* ln(VC / VD).

  1. Stage 4 → 1 (D → A): Reversible Adiabatic (Isentropic) Compression (TC → TH). The cylinder is again thermally insulated (QDA = 0, Δ*S*DA = 0) and compressed from VD back to its initial state (PA, VA, TH). The adiabatic compression work WDA = −*nC*V,m(TH − TC) cancels WBC, and the adiabatic trajectory obeys TCVDγ−1 = THVAγ−1.
Cycle StageProcess TypeHeat Transfer (Q)Mechanical Work (W = ∫*P* d*V*)Internal Energy Change (Δ*U*)Entropy Change (Δ*S*)
1. A → BIsothermal Expansion (TH)+*nRT*H ln(VB/VA)+*nRT*H ln(VB/VA)0+*nR* ln(VB/VA)
2. B → CAdiabatic Expansion (TH → TC)0+*nC*V,m(TH − TC)−*nC*V,m(TH − TC)0
3. C → DIsothermal Compression (TC)−*nRT*C ln(VC/VD)−*nRT*C ln(VC/VD)0−*nR* ln(VC/VD)
4. D → AAdiabatic Compression (TC → TH)0−*nC*V,m(TH − TC)+*nC*V,m(TH − TC)0
Full CycleReversible Closed LoopQH − |*Q*C|Wnet = (TH − TC) Δ*S*00

Efficiency Proof and the Temperature–Entropy (T–S) Diagram

Dividing the adiabatic relation for Stage 2 (THVBγ−1 = TCVCγ−1) by the adiabatic relation for Stage 4 (THVAγ−1 = TCVDγ−1) yields (VB / VA)γ−1 = (VC / VD)γ−1, which simplifies to the volume compression symmetry VB / VA = VC / VD. Substituting this identity into the ratio of rejected heat to absorbed heat eliminates the logarithm and the gas constant nR:

|*Q*C| / QH = [nRTC ln(VC / VD)] / [nRTH ln(VB / VA)] = TC / TH

Consequently, the net mechanical work output over the cycle is Wnet = QH − |*Q*C| = nR(TH − TC) ln(VB / VA), and the thermal efficiency is η = Wnet / QH = 1 − TC / TH. On a temperature–entropy (T–S) diagram, the Carnot cycle simplifies from a curved lens on the P–V plane into a rectangle bounded horizontally by the two isothermals T = TH and T = TC and vertically by the two isentropes S = S1 and S = S2. The absorbed heat is the total rectangular area under the top isotherm, QH = TH(S2 − S1) = TH Δ*S*; the rejected waste heat is the rectangular area under the bottom isotherm, |*Q*C| = TC Δ*S*; and the net work enclosed by the cycle is the area of the rectangle, Wnet = (TH − TC) Δ*S*.

Carnot's Theorem, the Clausius Inequality, and Entropy

Proof via the Kelvin–Planck and Clausius Postulates

Carnot's theorem consists of two propositions: (1) no irreversible heat engine operating between reservoirs at TH and TC can be more efficient than a reversible Carnot engine operating between the same reservoirs, and (2) all reversible heat engines operating between TH and TC have the same efficiency η = 1 − TC / TH, independent of their working fluid.

To prove this by contradiction, suppose a hypothetical engine X operated between TH and TC with efficiency ηX > ηCarnot. If engine X absorbs heat QH from the hot reservoir, it produces work WX = ηXQH > WCarnot. Because the Carnot cycle is reversible, we can use part of WX to drive the Carnot engine in reverse as a refrigerator, pumping heat QH back into the hot reservoir by extracting QH − WCarnot from the cold reservoir. The hot reservoir experiences zero net heat change, while the composite device extracts net heat WX − WCarnot > 0 from the single cold reservoir at TC and converts 100% of it into mechanical work Wnet = WX − WCarnot > 0 in a cyclic process—violating the Kelvin–Planck statement of the second law of thermodynamics. Equivalently, if all work WX were used to drive the reversed Carnot engine, net heat would flow spontaneously from the cold reservoir to the hot reservoir without external work, violating the Clausius statement of the second law.

The Clausius Inequality and Irreversibility

Because any real engine has efficiency ηreal = 1 − |*Q*C| / QH ≤ 1 − TC / TH, rearranging algebraic terms with signed heat transfers (QH > 0 entering the system, QC = −|*Q*C| < 0 leaving the system) yields QH / TH + QC / TC ≤ 0. Generalizing to an arbitrary cycle exchanging infinitesimal heat increments δ*Q* with a continuous sequence of reservoirs at temperature T gives the Clausius inequality (1865):

∮ (δ*Q* / T) ≤ 0

where equality holds if and only if the cycle is reversible. For any reversible cycle, ∮ δ*Q*rev / T = 0 implies that the line integral ∫12 δ*Q*rev / T depends only on the initial and final equilibrium states, defining the state function entropy: Δ*S* = S2 − S1 = ∫12 δ*Q*rev / T. In a real irreversible engine where internal friction or finite temperature gradients generate entropy Δ*S*gen > 0 per cycle, the lost work is quantified by the Gouy–Stodola theorem: Wlost = WCarnot − Wreal = TC Δ*S*gen.

Carnot Refrigerators, Heat Pumps, and Geophysical Heat Engines

Reversed Carnot Cycle and Coefficient of Performance (COP)

When every step of the Carnot cycle is executed in the counterclockwise direction on the P–V and T–S diagrams, mechanical work W is input to the working fluid to extract heat |*Q*C| from the cold reservoir at TC and reject heat |*Q*H| = |*Q*C| + W into the warm reservoir at TH. The performance of a refrigerator or air conditioner is measured by its coefficient of performance (COPR), defined as the cooling heat extracted per unit of work input:

COPR,Carnot = |*Q*C| / W = |*Q*C| / (|*Q*H| − |*Q*C|) = TC / (TH − TC)

For a household freezer operating between TC = 255 K (−18 °C) and kitchen air at TH = 298 K (25 °C), the maximum theoretical COPR is 255 / (298 − 255) = 5.93 (meaning 1 J of electrical work can pump at most 5.93 J of thermal energy out of the freezer). For a heat pump used to warm a building at TH by extracting heat from cold outdoor air or ground at TC, the desired output is |*Q*H|, giving:

COPHP,Carnot = |*Q*H| / W = |*Q*H| / (|*Q*H| − |*Q*C|) = TH / (TH − TC) = COPR,Carnot + 1

Because TH > TH − TC, a reversible heat pump always delivers more thermal energy |*Q*H| to a building than direct Joule electrical resistance heating (where COP = 1).

Finite-Time Thermodynamics and Hurricane Heat Engines

Because a reversible isothermal heat transfer requires an infinitesimal temperature difference Δ*T* → 0 between the reservoir and working fluid, a true Carnot engine would require an infinite cycle period to transfer finite heat, producing zero mechanical power output (P = W / τ → 0). In finite-time (endoreversible) thermodynamics developed by Curzon and Ahlborn (1975), optimizing a Carnot-like engine with finite thermal conductance for maximum power output rather than maximum efficiency yields the Curzon–Ahlborn efficiency:

ηCA = 1 − √(TC / TH)

This formula closely approximates the observed operational efficiencies of real coal, nuclear, and geothermal power plants. For instance, a steam plant operating between TH = 838 K (565 °C) and TC = 298 K (25 °C) has a Carnot limit of ηCarnot = 64.4%, an observed plant efficiency near 40%, and a Curzon–Ahlborn prediction of ηCA = 1 − √(298/838) = 40.4%.

In atmospheric physics, meteorologist Kerry Emanuel (1986) demonstrated that a mature tropical cyclone (hurricane) functions as a natural geophysical Carnot heat engine: surface air spirals isothermally inward toward the low-pressure eye over the warm tropical ocean at TH ≈ 300 K (absorbing latent heat of H2O vaporization and isothermal expansion heat), ascends adiabatically within the eyewall convective clouds to the tropopause outflow layer at TC ≈ 200 K (where it radiates infrared heat to space), and subsides at large radii. With ηCarnot = (300 − 200) / 300 ≈ 33%, the balance between Carnot mechanical work generation and surface frictional dissipation sets the theoretical maximum potential intensity (wind speed) of hurricanes on Earth.

Frequently Asked Questions

Why can no heat engine ever reach 100% thermal efficiency?

By the Carnot efficiency equation ηmax = 1 − TC / TH, achieving η = 1 (100% conversion of heat QH into work W) would require either an infinitely hot heat source (TH → ∞) or a cold sink at absolute zero (TC = 0 K). The third law of thermodynamics (Nernst heat theorem) prohibits reaching TC = 0 K in any finite number of steps, and on Earth the ambient atmosphere or ocean limits TC to roughly 285–300 K. Physically, heat QH entering the engine carries entropy Δ*S* = QH / TH; because mechanical work W carries zero entropy, the working fluid must dump at least |*Q*C| = TC Δ*S* of waste heat into the cold sink to reset its entropy at the end of each cycle.

Why don't practical steam power plants or automobile engines run on the Carnot cycle?

In a gas-phase Carnot engine, the isothermal expansion and compression stages occur at very low pressure ratios while the adiabatic stages require huge cylinder volume ratios and very high peak pressures, resulting in a very low work ratio and mean effective pressure—meaning friction between the piston and cylinder walls consumes a large fraction of the net work. Furthermore, isothermal heat transfer in a gas is extremely slow compared to constant-pressure phase-change boiling and condensation. Consequently, steam power plants use the Rankine cycle, spark-ignition engines use the Otto cycle, and gas turbines use the Brayton cycle.

References

  1. Carnot, S. (1824). Réflexions sur la puissance motrice du feu et sur les machines propres à développer cette puissance. Bachelier, Paris. https://gallica.bnf.fr/ark:/12148/bpt6k655562
  2. Clausius, R. (1850). "Über die bewegende Kraft der Wärme und die Gesetze, welche sich daraus für die Wärmelehre selbst ableiten lassen." Annalen der Physik und Chemie, 155(3), 368–397. doi:10.1002/andp.18501550306
  3. Curzon, F. L., & Ahlborn, B. (1975). "Efficiency of a Carnot engine at maximum power output." American Journal of Physics, 43(1), 22–24. doi:10.1119/1.10023
  4. Emanuel, K. A. (1986). "An Air-Sea Interaction Theory for Tropical Cyclones. Part I: Steady-State Maintenance." Journal of the Atmospheric Sciences, 43(6), 585–605. doi:10.1175/1520-0469(1986)043<0585:AASITF>2.0.CO;2043<0585:AASITF>2.0.CO;2)
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